Notes
two hexagons and a square solution

Solution to the Two Hexagons and a Square Puzzle

Two Hexagons and a Square

Two regular hexagons, and a square of side length 22. What’s the shaded area?

Solution by Lengths in a Regular Hexagon

Two hexagons and a square labelled

The side length of the square is the same as the smaller diameter of the inner hexagon, which is 3\sqrt{3} times the side length. So the side length of the inner hexagon is 23\frac{2}{\sqrt{3}}. The excess CDC D is half of what is left over, so has length:

12(223)=113 \frac{1}{2} \left(2 - \frac{2}{\sqrt{3}}\right) = 1 - \frac{1}{\sqrt{3}}

This is the same as the length of ABA B. Since the length of OAO A is the same as the side length of the inner hexagon, the length of OBO B, which is the same as the side length of the outer hexagon, is:

23+113=1+13 \frac{2}{\sqrt{3}} + 1 - \frac{1}{\sqrt{3}} = 1 + \frac{1}{\sqrt{3}}

The area of a hexagon is 332\frac{3\sqrt{3}}{2} times the square of its side length, so the area of the shaded region is:

332((1+13) 2(1+13) 2)=6 \frac{3\sqrt{3}}{2} \left( \left(1 + \frac{1}{\sqrt{3}}\right)^2 - \left(1 + \frac{1}{\sqrt{3}}\right)^2 \right) = 6