Notes
triangle in circle in triangle in semi-circle solution

Triangle in Circle in Triangle in Semi-Circle

Triangle in Circle in Triangle in Semi-Circle

A triangle in a circle in a triangle in a semicircle … what’s the angle?

Solution by Angle in a Semi-Circle and Alternate Segment Theorem

Triangle in circle in triangle in semi-circle labelled

With the points labelled as above, angle AE^CA \hat{E} C is the angle in a semi-circle so is a right-angle. As AEA E and CEC E are both tangent to the smaller circle, FEF E and EDE D are the same length, so triangle FEDF E D is isosceles and right-angled. Therefore, angle DF^ED \hat{F} E is 45 45^\circ. By the alternate segment theorem, angle DB^FD \hat{B} F is also 45 45^\circ.