Notes
circle in pentagon in semi-circle solution

Solution to the Circle In Pentagon in Semi-Circle Puzzle

Circle In Pentagon in Semi-Circle

A circle in a regular pentagon in a semicircle. What fraction of the semicircle is shaded?

Solution by Lengths in a Regular Pentagon

Circle in a pentagon in a semi-circle labelled

The radius of the small circle is the radius of the incircle of the regular pentagon. The radius of the semi-circle is the radius of the incircle added to the radius of the circumcircle of the regular pentagon. From lengths in a regular pentagon, these radius of the circumcircle, RR, and incircle, rr, are related by 2r=ϕR2 r = \phi R where ϕ\phi is the golden ratio. With this notation, the radius of the semi-circle is r+R=(1+2ϕ)rr + R = (1 + \frac{2}{\phi}) r. The area of the incircle is πr 2\pi r^2 and the area of the semi-circle is:

12π(r+R) 2 =12π(1+2ϕ) 2r 2 =12ϕ 2π(ϕ+2) 2r 2 =12ϕ 2πr 2(ϕ 2+4ϕ+4) =12ϕ 2πr 25ϕ 2 =52πr 2 \begin{aligned} \frac{1}{2} \pi (r + R)^2 &= \frac{1}{2} \pi (1 + \frac{2}{\phi})^2 r^2 \\ &= \frac{1}{2 \phi^2} \pi (\phi + 2)^2 r^2 \\ &=\frac{1}{2 \phi^2} \pi r^2 (\phi^2 + 4 \phi + 4) \\ &=\frac{1}{2 \phi^2} \pi r^2 5 \phi^2 \\ &= \frac{5}{2} \pi r^2 \end{aligned}

Therefore the fraction of the semi-circle that is shaded is 25\frac{2}{5}.