# Solution to the [[Two Circles in an Equilateral Triangle]] Puzzle +-- {.image} [[TwoCirclesinanEquilateralTriangle.png:pic]] > What’s the side length of this equilateral triangle? Both circles have area $3$. =-- ## Solution by Lengths in an [[Equilateral Triangle]] +-- {.image} [[TwoCirclesinanEquilateralTriangleAnnotated.png:pic]] =-- With the points labelled as above, triangle $A E B$ is half of an [[equilateral triangle]] so the length of $A E$ is twice that of $E B$. This means that the length of $A D$ is five times the radius of one of the circles, which is $\sqrt{3}$. The height of an equilateral triangle is $\frac{\sqrt{3}}{2}$ times the length of one of its sides, so the side of the outer equilateral triangle is: $$ \frac{2}{\sqrt{3}} \times 5 \sqrt{3} = 10 $$