# Solution to the Seven Hexagons Puzzle +-- {.image} [[SevenHexagons.png:pic]] > Seven regular hexagons. What fraction is shaded? =-- ## Solution by [[hexagon|Lengths in a Regular Hexagon]] and [[Pythagoras' Theorem]] +-- {.image} [[SevenHexagonsLabelled.png:pic]] =-- In the diagram above, let $x$ be the side length of one of the hexagons. Using the calculations on [[hexagon|lengths in a regular hexagon]], the line segment $A C$ has length $3\sqrt{3} x$. Applying [[Pythagoras' theorem]] to triangle $A B C$ shows that the length of $A B$ is $\sqrt{28}x$. This is the diameter of the large circle so its area is $7 \pi x^2$. The diameter of the smaller circles is the same as the shorter diameter of the [[hexagons]], namely $\sqrt{3} x$, so their combined area is $7 \times \pi \frac{3}{4} x^2 = \frac{3}{4} \times 7 \pi x^2$. Therefore, $\frac{3}{4}$ of the large circle is shaded.