# Solution to the Angle Formed by Two Squares Puzzle +-- {.image} [[AngleFormedbyTwoSquares.png:pic]] > These squares are the same size. What’s the angle? =-- ## Solution by [[Equilateral Triangles]] +-- {.image} [[AngleFormedbyTwoSquaresLabelled.png:pic]] =-- With the points labelled as above, triangle $C B D$ has the property that it is [[right-angled triangle|right-angled]] at $D$ as that is where the diagonals of the square cross. Also, the length of $C B$ is double that of $B D$. This means that triangle $C B D$ is a half of an [[equilateral triangle]]. Therefore, angle $D \hat{C} B$ is $30^\circ$ and so the requested angle is $75^\circ$.