Notes
three equal area rectangles solution

Three Equal Area Rectangles

Three Equal Area Rectangles

All three of these rectangles have the same area. What is it?

Solution by Pythagoras' Theorem

Three equal area rectangles labelled

In the above diagram, consider the right-angled triangle ABCA B C. Let xx be the length of ADA D, then ABA B has length x+10x + 10 and CBC B has length x10x - 10. Let yy be the length of ACA C. Then applying Pythagoras' theorem to triangle ABCA B C yields:

y 2=(x+10) 2+(x10) 2=2x 2+200 y^2 = (x + 10)^2 + (x - 10)^2 = 2 x^2 + 200

As the rectangles have the same area, also 7y=10x7 y = 10 x so y=107xy = \frac{10}{7} x. Putting this into the above equation,

10049x 2=2x 2+200 \frac{100}{49} x^2 = 2 x^2 + 200

which simplifies to 249x 2=200\frac{2}{49} x^2 = 200, and this simplifies further to x=70x = 70 and so y=100y = 100. The area of the rectangles is therefore 700700.