Notes
stacked boxes in circles in squares solution

Solution to the Stacked Boxes in Circles in Squares Puzzle

Stacked Boxes in Circles in Squares

If the area of each pink square is 11, what’s the area of the blue squares in each box as the sequence continues? Is the total area of the blue squares finite?

Solution by Pythagoras' Theorem

Stacked boxes in circles in squares with diagonals

As each pink square has area 11, it has side length 11, and so the diameter of each circle is 11 and therefore the diagonal of each rectangle is 11.

Consider the general case, and let nn be the number of little squares. Let dd be the side length of one of the little squares. Then Pythagoras' Theorem states that:

1 2=d 2+(nd) 2=(n 2+1)d 2 1^2 = d^2 + (n d)^2 = (n^2 + 1) d^2

Therefore the total area of the nn little squares is nn 2+1\frac{n}{n^2 + 1}.

The sum of the areas is therefore:

n=1 nn 2+1 \sum_{n=1}^\infty \frac{n}{n^2+1}

Since n1n \ge 1, n 2+1n 2+nn^2 + 1 \le n^2 + n so nn 2+1nn 2+n=1n+1\frac{n}{n^2+1} \ge \frac{n}{n^2+n} = \frac{1}{n+1}. So this series is the harmonic series (except the first term) and so diverges.