Notes
multiple semi-circles in a circle solution

Solution to the Multiple Semi-Circles in a Circle Puzzle

Multiple Semi-Circles in a Circle

The green area is double the yellow area. What fraction of the total is shaded?

Solution by Area of a Circle

Multiple semi-circles in a circle labelled

As in the diagram, let aa, bb, and cc be the radii of the three smallest circles. The upper green circle has radius a+ba + b, the lower green radius b+cb + c, and the full circle has radius a+b+ca + b + c.

The area of the upper green region is:

12π(a+b) 212πa 212πb 2=12π(a 2+2ab+b 2a 2b 2)=πab \frac{1}{2} \pi (a + b)^2 - \frac{1}{2} \pi a^2 - \frac{1}{2} \pi b^2 = \frac{1}{2} \pi( a^2 + 2 a b + b^2 - a^2 - b^2 ) = \pi a b

Likewise, the area of the lower green region is πbc\pi b c. The total green area is thus πb(a+c) \pi b (a + c). This is double the yellow area, which is πb 2\pi b^2, so a+c=2ba + c = 2 b and the total shaded area is 3πb 23 \pi b^2.

As a+c=2ba + c = 2 b, the radius of the outer circle is 3b3 b and so its area is 9πb 29 \pi b^2. The fraction of this that is shaded is therefore 13\frac{1}{3}.