Notes
five equilateral triangles ii solution

Solution to the Five Equilateral Triangles II Puzzle

Five Equilateral Triangles II

The five triangles are equilateral. What’s the angle?

Solution by Rotation, Angles in Isosceles Triangles, Corresponding Angles, and Angles at a Point on a Straight Line

Five equilateral triangles ii labelled

In the above diagram, triangle ABFA B F is another large equilateral triangle and HIJH I J is another small one.

Triangle AGJA G J is obtained from triangle ABFA B F by rotating 120 120^\circ about AA. This also takes triangle EDFE D F to triangle HIJH I J. Therefore, line segment AIA I is the rotation by 120 120^\circ of line segment ADA D about AA. Hence angle DA^ID \hat{A} I is 120 120^\circ and triangle ADIA D I is isosceles. This means that angle ID^AI \hat{D} A is 30 30^\circ since angles in a triangle add up to 180 180^\circ.

Finally, line segments CJC J and DID I are parallel, so angles JK^AJ \hat{K} A and ID^AI \hat{D} A are equal as they are corresponding angles. Then angle AK^C=180 30 =150 A \hat{K} C = 180^\circ - 30^\circ = 150^\circ since angles at a point on a straight line add up to 180 180^\circ.

Solution by Invariance Principle

The relative sizes of the equilateral triangles is not specified, and varying this leads to two configurations where the answer is more clear. In both, the lines have to be extended to ensure that the angle is well-defined.

Five equilateral triangles ii invariance A

In this configuration, all the equilateral triangles are the same size. The extra line bisects? one of the equilateral triangles, meaning that the acute angle is half of 60 60^\circ and so the requested angle is 150 150^\circ.

Five equilateral triangles ii invariance B

In this configuration, the smaller equilateral triangles have been shrunk down to a point. The requested angle is 150 150^\circ by a similar argument.